What is (2i-1)^2*(4/(1-i)+(2-i)/(1+i)) ?

The solution to (2i-1)^2*(4/(1-i)+(2-i)/(1+i)) is -11/2-23/2 i

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simplify (2i-1)^2*(4/(1-i)+(2-i)/(1+i))

simplify

(2 i - 1)^{2} \cdot (\frac{4}{1 - i} + \frac{2 - i}{1 + i})

- \frac{11}{2} - \frac{23}{2} i

Solution steps

(2 i - 1)^{2} (\frac{4}{1 - i} + \frac{2 - i}{1 + i})

Expand

(2 i - 1)^{2} : - 4 i - 3

= (- 4 i - 3) (\frac{4}{1 - i} + \frac{2 - i}{1 + i})

Apply FOIL method

(- 4 i - 3) (\frac{4}{1 - i} + \frac{2 - i}{1 + i}) : - \frac{11}{2} - \frac{23}{2} i

= - \frac{11}{2} - \frac{23}{2} i

7 (2 x - 1) - 3 = 6 + 6 x

(\frac{3}{2}) (\frac{3}{2})

(t + 3)^{2} - (t + 3) - 12 = 0

t^{2} - 2 t + 1

\frac{3}{4} \cdot \frac{4}{9} \cdot \frac{2}{6}

What is (2i-1)^2*(4/(1-i)+(2-i)/(1+i)) ?
The solution to (2i-1)^2*(4/(1-i)+(2-i)/(1+i)) is -11/2-23/2 i