What are the solutions to the equation (x-7)*(x-12)=0 ?

The solutions to the equation (x-7)*(x-12)=0 are x=7,x=12

Find the zeros of (x-7)*(x-12)=0

The zeros of (x-7)*(x-12)=0 are x=7,x=12

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(x - 7) \cdot (x - 12) = 0

x = 7, x = 12

Solution steps

(x - 7) (x - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 7 = 0 or x - 12 = 0

Solve

x - 7 = 0 : x = 7

Solve

x - 12 = 0 : x = 12

The solutions to the quadratic equation are:

x = 7, x = 12

2 x + 7 \geq 31

3 x^{2} + 6 x + 6 = 0

x^{2} + 8 x + 28 = 0

(\frac{a ^{6}}{a ^{7}})^{- 3}

\frac{( x - 2 )}{3} - \frac{( 3 x - 1 )}{4} = x + \frac{( 3 x + 2 )}{5}

What are the solutions to the equation (x-7)*(x-12)=0 ?
The solutions to the equation (x-7)*(x-12)=0 are x=7,x=12
Find the zeros of (x-7)*(x-12)=0
The zeros of (x-7)*(x-12)=0 are x=7,x=12