What are the solutions to the equation r^2-18r+81=0 ?

The solutions to the equation r^2-18r+81=0 are r=9

Find the zeros of r^2-18r+81=0

The zeros of r^2-18r+81=0 are r=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} - 18 r + 81 = 0

r = 9

Solution steps

r^{2} - 18 r + 81 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 81 = 0

r_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 1}

r = \frac{- ( - 18 )}{2 \cdot 1}

\frac{- ( - 18 )}{2 \cdot 1} = 9

r = 9

The solution to the quadratic equation is:

r = 9

525

16 r^{2} + 40 r + 25

x^{2} - 16 x + 65 = 0

\frac{c}{2} \geq 4

6 x - 4 \leq 2 + 8 x

What are the solutions to the equation r^2-18r+81=0 ?
The solutions to the equation r^2-18r+81=0 are r=9
Find the zeros of r^2-18r+81=0
The zeros of r^2-18r+81=0 are r=9