What are the solutions to the equation -32/400 x^2+x+3=0 ?

The solutions to the equation -32/400 x^2+x+3=0 are x=-5/2 ,x=15

Find the zeros of -32/400 x^2+x+3=0

The zeros of -32/400 x^2+x+3=0 are x=-5/2 ,x=15

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- \frac{32}{400} x^{2} + x + 3 = 0

x = - \frac{5}{2}, x = 15

Decimal Notation

x = - 2.5, x = 15

Solution steps

- \frac{32}{400} x^{2} + x + 3 = 0

Multiply both sides by

400

- 32 x^{2} + 400 x + 1200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 ( - 32 ) \cdot 1200}{2 ( - 32 )}

40 0^{2} - 4 (- 32) \cdot 1200 = 560

x_{1, 2} = \frac{- 400 \pm 560}{2 ( - 32 )}

Separate the solutions

x_{1} = \frac{- 400 + 560}{2 ( - 32 )}, x_{2} = \frac{- 400 - 560}{2 ( - 32 )}

x = \frac{- 400 + 560}{2 ( - 32 )} : - \frac{5}{2}

x = \frac{- 400 - 560}{2 ( - 32 )} : 15

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = 15

6 + \frac{4}{4} + \frac{3}{3}

x^{2} + 25 = 10 x

12 c^{2} + 46 c + 40

45 q^{3} - 20 q

What are the solutions to the equation -32/400 x^2+x+3=0 ?
The solutions to the equation -32/400 x^2+x+3=0 are x=-5/2 ,x=15
Find the zeros of -32/400 x^2+x+3=0
The zeros of -32/400 x^2+x+3=0 are x=-5/2 ,x=15