What are the solutions to the equation 0=x^2-6x+9 ?

The solutions to the equation 0=x^2-6x+9 are x=3

Find the zeros of 0=x^2-6x+9

The zeros of 0=x^2-6x+9 are x=3

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0 = x^{2} - 6 x + 9

x = 3

Solution steps

0 = x^{2} - 6 x + 9

Switch sides

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

(x + 1)^{3} - (y - 2)^{3}

(\frac{1}{4})^{8}

\frac{x ^{8}}{x ^{5}}

\frac{2 - 2 x}{9} = 10

2 n^{2} + 9 n - 5

What are the solutions to the equation 0=x^2-6x+9 ?
The solutions to the equation 0=x^2-6x+9 are x=3
Find the zeros of 0=x^2-6x+9
The zeros of 0=x^2-6x+9 are x=3