What are the solutions to the equation x^2+125=0 ?

The solutions to the equation x^2+125=0 are x=5sqrt(5)i,x=-5sqrt(5)i

Find the zeros of x^2+125=0

The zeros of x^2+125=0 are x=5sqrt(5)i,x=-5sqrt(5)i

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x^{2} + 125 = 0

x = 55 i, x = - 55 i

Solution steps

x^{2} + 125 = 0

Move

125

to the right side

x^{2} = - 125

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 125, x = - - 125

- 125 = 55 i

- - 125 = - 55 i

x = 55 i, x = - 55 i

x^{2} + 5 x - 50

x^{3} + 4 x^{2} - 11 x - 44

(\frac{3}{5})^{8}

12 < \frac{u}{7}

x^{2 - 1}

What are the solutions to the equation x^2+125=0 ?
The solutions to the equation x^2+125=0 are x=5sqrt(5)i,x=-5sqrt(5)i
Find the zeros of x^2+125=0
The zeros of x^2+125=0 are x=5sqrt(5)i,x=-5sqrt(5)i