What are the solutions to the equation v^2+4v-5=0 ?

The solutions to the equation v^2+4v-5=0 are v=1,v=-5

Find the zeros of v^2+4v-5=0

The zeros of v^2+4v-5=0 are v=1,v=-5

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v^{2} + 4 v - 5 = 0

v = 1, v = - 5

Solution steps

v^{2} + 4 v - 5 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

v_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 4 + 6}{2 \cdot 1}, v_{2} = \frac{- 4 - 6}{2 \cdot 1}

v = \frac{- 4 + 6}{2 \cdot 1} : 1

v = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

v = 1, v = - 5

20 x^{2} + 11 x - 3

8 (- n - 18) + 37 = - 8 (- 4 n - 8) - 11

\frac{1}{2} \cdot \frac{2}{2}

4 x^{2} = 81

4 s^{2} - 21 s + 5

What are the solutions to the equation v^2+4v-5=0 ?
The solutions to the equation v^2+4v-5=0 are v=1,v=-5
Find the zeros of v^2+4v-5=0
The zeros of v^2+4v-5=0 are v=1,v=-5