What is |y+1|< 2/(|y|) ?

The solution to |y+1|< 2/(|y|) is -2<y<0\lor 0<y<1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|y+1|< 2/(|y|)

∣ y + 1 ∣ < \frac{2}{∣ y ∣}

- 2 < y < 0 or 0 < y < 1

Interval Notation

(- 2, 0) \cup (0, 1)

Solution steps

∣ y + 1 ∣ < \frac{2}{∣ y ∣}

Find positive and negative intervals

y < - 1, - 1 \leq y < 0, y \geq 0

Solve the inequality for each interval

- 2 < y < - 1 or - 1 \leq y < 0 or 0 < y < 1

Merge Overlapping Intervals

- 2 < y < 0 or 0 < y < 1

10000 0^{\frac{3}{5}}

\frac{3}{4} + (\frac{1}{3} \div \frac{1}{6}) - (- \frac{1}{2})

(- \frac{1}{3})^{\frac{4}{5}} \cdot (\frac{1}{3})^{\frac{3}{5}}

(x^{5})^{\frac{1}{9}}

2^{- 6} = \frac{1}{64}