What are the solutions to the equation (z+9)^2=-25 ?

The solutions to the equation (z+9)^2=-25 are z=5i-9,z=-5i-9

Find the zeros of (z+9)^2=-25

The zeros of (z+9)^2=-25 are z=5i-9,z=-5i-9

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(z + 9)^{2} = - 25

z = 5 i - 9, z = - 5 i - 9

Solution steps

(z + 9)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 9 = - 25 : z = 5 i - 9

Solve

z + 9 = - - 25 : z = - 5 i - 9

The solutions to the quadratic equation are:

z = 5 i - 9, z = - 5 i - 9

- 720 x + 720 - (i \cdot 40) x + 120 x + 10 (720 - 72 x) = 0

2 x (x - 4) - 3 x > - 2

7 x^{2} - 23 x + 6

2^{x} 3^{x} \leq 7776

(\frac{5}{3})^{- 0.5}

What are the solutions to the equation (z+9)^2=-25 ?
The solutions to the equation (z+9)^2=-25 are z=5i-9,z=-5i-9
Find the zeros of (z+9)^2=-25
The zeros of (z+9)^2=-25 are z=5i-9,z=-5i-9