What is (2(x+2))/5 <(3(x-2))/(10) ?

The solution to (2(x+2))/5 <(3(x-2))/(10) is x<-14

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(2(x+2))/5 <(3(x-2))/(10)

\frac{2 ( x + 2 )}{5} < \frac{3 ( x - 2 )}{10}

x < - 14

Interval Notation

(- \infty, - 14)

Solution steps

\frac{2 ( x + 2 )}{5} < \frac{3 ( x - 2 )}{10}

Multiply both sides by

10

4 (x + 2) < 3 (x - 2)

Expand

4 (x + 2) : 4 x + 8

Expand

3 (x - 2) : 3 x - 6

4 x + 8 < 3 x - 6

Move

8

to the right side

4 x < 3 x - 14

Move

3 x

to the left side

x < - 14

5 x - 6 \leq 3 (2 + 3 x)

21 = 8 + 4 (c - 7)

\frac{1}{x + 1} \leq \frac{4}{x}

\frac{1}{4} - \frac{2}{3}

- 2 + 3 x \geq 14

What is (2(x+2))/5 <(3(x-2))/(10) ?
The solution to (2(x+2))/5 <(3(x-2))/(10) is x<-14