What are the solutions to the equation 5x^2+5x-1=0 ?

The solutions to the equation 5x^2+5x-1=0 are x=(-sqrt(5)+3)/(2sqrt(5)),x=-(sqrt(5)+3)/(2sqrt(5))

Find the zeros of 5x^2+5x-1=0

The zeros of 5x^2+5x-1=0 are x=(-sqrt(5)+3)/(2sqrt(5)),x=-(sqrt(5)+3)/(2sqrt(5))

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5 x^{2} + 5 x - 1 = 0

x = \frac{- 5 + 3}{2 5}, x = - \frac{5 + 3}{2 5}

Decimal Notation

x = 0.17082 \dots, x = - 1.17082 \dots

Solution steps

5 x^{2} + 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

5^{2} - 4 \cdot 5 (- 1) = 35

x_{1, 2} = \frac{- 5 \pm 3 5}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 5 + 3 5}{2 \cdot 5}, x_{2} = \frac{- 5 - 3 5}{2 \cdot 5}

x = \frac{- 5 + 3 5}{2 \cdot 5} : \frac{- 5 + 3}{2 5}

x = \frac{- 5 - 3 5}{2 \cdot 5} : - \frac{5 + 3}{2 5}

The solutions to the quadratic equation are:

x = \frac{- 5 + 3}{2 5}, x = - \frac{5 + 3}{2 5}

x^{25}

9 x^{2} + 11 x + 2 = 0

5 x^{2} + 8 x + 3

lo g_{7} (7^{3})

x^{2} - 7 x + 10

What are the solutions to the equation 5x^2+5x-1=0 ?
The solutions to the equation 5x^2+5x-1=0 are x=(-sqrt(5)+3)/(2sqrt(5)),x=-(sqrt(5)+3)/(2sqrt(5))
Find the zeros of 5x^2+5x-1=0
The zeros of 5x^2+5x-1=0 are x=(-sqrt(5)+3)/(2sqrt(5)),x=-(sqrt(5)+3)/(2sqrt(5))