What are the solutions to the equation 8x^2-3x+3=0 ?

The solutions to the equation 8x^2-3x+3=0 are x= 3/16+i(sqrt(87))/(16),x= 3/16-i(sqrt(87))/(16)

Find the zeros of 8x^2-3x+3=0

The zeros of 8x^2-3x+3=0 are x= 3/16+i(sqrt(87))/(16),x= 3/16-i(sqrt(87))/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} - 3 x + 3 = 0

x = \frac{3}{16} + i \frac{87}{16}, x = \frac{3}{16} - i \frac{87}{16}

Solution steps

8 x^{2} - 3 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 8 \cdot 3}{2 \cdot 8}

Simplify

(- 3)^{2} - 4 \cdot 8 \cdot 3 : 87 i

x_{1, 2} = \frac{- ( - 3 ) \pm 87 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 87 i}{2 \cdot 8}, x_{2} = \frac{- ( - 3 ) - 87 i}{2 \cdot 8}

x = \frac{- ( - 3 ) + 87 i}{2 \cdot 8} : \frac{3}{16} + i \frac{87}{16}

x = \frac{- ( - 3 ) - 87 i}{2 \cdot 8} : \frac{3}{16} - i \frac{87}{16}

The solutions to the quadratic equation are:

x = \frac{3}{16} + i \frac{87}{16}, x = \frac{3}{16} - i \frac{87}{16}

\frac{2}{5} x = 9 - 5

9 x - 7 \leq 38

3 x^{2} - 18 x + 24 = 0

3 x^{2} - 2 x = 8

\frac{- 72}{6}

What are the solutions to the equation 8x^2-3x+3=0 ?
The solutions to the equation 8x^2-3x+3=0 are x= 3/16+i(sqrt(87))/(16),x= 3/16-i(sqrt(87))/(16)
Find the zeros of 8x^2-3x+3=0
The zeros of 8x^2-3x+3=0 are x= 3/16+i(sqrt(87))/(16),x= 3/16-i(sqrt(87))/(16)