What are the solutions to the equation x^2-12-11x=11 ?

The solutions to the equation x^2-12-11x=11 are x=(11+sqrt(213))/2 ,x=(11-sqrt(213))/2

Find the zeros of x^2-12-11x=11

The zeros of x^2-12-11x=11 are x=(11+sqrt(213))/2 ,x=(11-sqrt(213))/2

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x^{2} - 12 - 11 x = 11

x = \frac{11 + 213}{2}, x = \frac{11 - 213}{2}

Decimal Notation

x = 12.79725 \dots, x = - 1.79725 \dots

Solution steps

x^{2} - 12 - 11 x = 11

Move

11

to the left side

x^{2} - 11 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot (- 23) = 213

x_{1, 2} = \frac{- ( - 11 ) \pm 213}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 213}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 213}{2 \cdot 1}

x = \frac{- ( - 11 ) + 213}{2 \cdot 1} : \frac{11 + 213}{2}

x = \frac{- ( - 11 ) - 213}{2 \cdot 1} : \frac{11 - 213}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 213}{2}, x = \frac{11 - 213}{2}

y^{2} - 196

\frac{36}{16}

1 - m^{3}

2 x + \frac{6 - 3 x}{4} < 4

\frac{3}{\frac{3}{2}}

What are the solutions to the equation x^2-12-11x=11 ?
The solutions to the equation x^2-12-11x=11 are x=(11+sqrt(213))/2 ,x=(11-sqrt(213))/2
Find the zeros of x^2-12-11x=11
The zeros of x^2-12-11x=11 are x=(11+sqrt(213))/2 ,x=(11-sqrt(213))/2