What are the solutions to the equation 24x^2+144x+216=0 ?

The solutions to the equation 24x^2+144x+216=0 are x=-3

Find the zeros of 24x^2+144x+216=0

The zeros of 24x^2+144x+216=0 are x=-3

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24 x^{2} + 144 x + 216 = 0

x = - 3

Solution steps

24 x^{2} + 144 x + 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 \cdot 24 \cdot 216}{2 \cdot 24}

14 4^{2} - 4 \cdot 24 \cdot 216 = 0

x_{1, 2} = \frac{- 144 \pm 0}{2 \cdot 24}

x = \frac{- 144}{2 \cdot 24}

\frac{- 144}{2 \cdot 24} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

x^{2} - 5 x + 6 \geq 0

\frac{5}{9} x = 10

0.8 x^{2} - 2 \cdot 3.8 \cdot 0.011 x + 0.01 1^{2} \cdot 0.8 = 0

2 x + 14 = 0

- 11 \leq 5 x - 1 \leq 9

What are the solutions to the equation 24x^2+144x+216=0 ?
The solutions to the equation 24x^2+144x+216=0 are x=-3
Find the zeros of 24x^2+144x+216=0
The zeros of 24x^2+144x+216=0 are x=-3