What are the solutions to the equation x^2+4x-9=x+1 ?

The solutions to the equation x^2+4x-9=x+1 are x=2,x=-5

Find the zeros of x^2+4x-9=x+1

The zeros of x^2+4x-9=x+1 are x=2,x=-5

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x^{2} + 4 x - 9 = x + 1

x = 2, x = - 5

Solution steps

x^{2} + 4 x - 9 = x + 1

Move

1

to the left side

x^{2} + 4 x - 10 = x

Move

x

to the left side

x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 1}, x_{2} = \frac{- 3 - 7}{2 \cdot 1}

x = \frac{- 3 + 7}{2 \cdot 1} : 2

x = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

4 x^{2} \cdot 4 x^{2}

8 x^{2} + 112 x + 392

x^{2} + 3 = 2 x

\frac{4}{7} x - \frac{10}{7} = - \frac{7}{4} x + \frac{1}{4}

2 n^{2} - 10 n - 48

What are the solutions to the equation x^2+4x-9=x+1 ?
The solutions to the equation x^2+4x-9=x+1 are x=2,x=-5
Find the zeros of x^2+4x-9=x+1
The zeros of x^2+4x-9=x+1 are x=2,x=-5