What is the answer to |x^2+3x-3|=4x+3 ?

The answer to |x^2+3x-3|=4x+3 is x=0\lor x=3

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|x^2+3x-3|=4x+3

x^{2} + 3 x - 3 = 4 x + 3

x = 0 or x = 3

Solution steps

x^{2} + 3 x - 3 = 4 x + 3

Find positive and negative intervals

x \leq \frac{- 21 - 3}{2}, \frac{- 21 - 3}{2} < x < \frac{21 - 3}{2}, x \geq \frac{21 - 3}{2}

Solve the inequality for each interval

No Solution or x = 0 or x = 3

x = 0 or x = 3

1 = 5 + p - p

3 x + 3 > 3

1 + 3 w \leq 10

8 x^{2} + 10 x + 2 = 0

(12) - (23 + 13 i)

What is the answer to |x^2+3x-3|=4x+3 ?
The answer to |x^2+3x-3|=4x+3 is x=0\lor x=3
Solve for x: |x^2+3x-3|=4x+3
The solution is x=0\lor x=3