What are the solutions to the equation v^2=19v ?

The solutions to the equation v^2=19v are v=19,v=0

Find the zeros of v^2=19v

The zeros of v^2=19v are v=19,v=0

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v^{2} = 19 v

v = 19, v = 0

Solution steps

v^{2} = 19 v

Move

19 v

to the left side

v^{2} - 19 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 0 = 19

v_{1, 2} = \frac{- ( - 19 ) \pm 19}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 19 ) + 19}{2 \cdot 1}, v_{2} = \frac{- ( - 19 ) - 19}{2 \cdot 1}

v = \frac{- ( - 19 ) + 19}{2 \cdot 1} : 19

v = \frac{- ( - 19 ) - 19}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

v = 19, v = 0

- 6 - 16 x^{4}

4 r^{2} - r - 8 = 0

\frac{- 2}{1}

2 (2^{x + y})

2 a^{2} - [a + [2 (a - 1) (a + 3)]] = 26

What are the solutions to the equation v^2=19v ?
The solutions to the equation v^2=19v are v=19,v=0
Find the zeros of v^2=19v
The zeros of v^2=19v are v=19,v=0