What are the solutions to the equation a^2-18a+68=3 ?

The solutions to the equation a^2-18a+68=3 are a=13,a=5

Find the zeros of a^2-18a+68=3

The zeros of a^2-18a+68=3 are a=13,a=5

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a^{2} - 18 a + 68 = 3

a = 13, a = 5

Solution steps

a^{2} - 18 a + 68 = 3

Move

3

to the left side

a^{2} - 18 a + 65 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 65 = 8

a_{1, 2} = \frac{- ( - 18 ) \pm 8}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 18 ) + 8}{2 \cdot 1}, a_{2} = \frac{- ( - 18 ) - 8}{2 \cdot 1}

a = \frac{- ( - 18 ) + 8}{2 \cdot 1} : 13

a = \frac{- ( - 18 ) - 8}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

a = 13, a = 5

\frac{56}{8}

\frac{5}{- 3 + 4 i}

\frac{2 2}{2}

\frac{6}{7} + (- \frac{5}{14})

lo g_{2} (2 x + 2) \geq 1

What are the solutions to the equation a^2-18a+68=3 ?
The solutions to the equation a^2-18a+68=3 are a=13,a=5
Find the zeros of a^2-18a+68=3
The zeros of a^2-18a+68=3 are a=13,a=5