What are the solutions to the equation 2p^2+9p-1=5p ?

The solutions to the equation 2p^2+9p-1=5p are p=(-2+sqrt(6))/2 ,p=-(2+sqrt(6))/2

Find the zeros of 2p^2+9p-1=5p

The zeros of 2p^2+9p-1=5p are p=(-2+sqrt(6))/2 ,p=-(2+sqrt(6))/2

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2 p^{2} + 9 p - 1 = 5 p

p = \frac{- 2 + 6}{2}, p = - \frac{2 + 6}{2}

Decimal Notation

p = 0.22474 \dots, p = - 2.22474 \dots

Solution steps

2 p^{2} + 9 p - 1 = 5 p

Move

5 p

to the left side

2 p^{2} + 4 p - 1 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 1) = 26

p_{1, 2} = \frac{- 4 \pm 2 6}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 4 + 2 6}{2 \cdot 2}, p_{2} = \frac{- 4 - 2 6}{2 \cdot 2}

p = \frac{- 4 + 2 6}{2 \cdot 2} : \frac{- 2 + 6}{2}

p = \frac{- 4 - 2 6}{2 \cdot 2} : - \frac{2 + 6}{2}

The solutions to the quadratic equation are:

p = \frac{- 2 + 6}{2}, p = - \frac{2 + 6}{2}

\frac{4}{2 2}

\frac{x ^{2}}{2} + \frac{10}{3} x + 2 = 0

k^{2} - 6 k

(x + 3) (x - 3)

x^{2} - 9 x + 7 = 0

What are the solutions to the equation 2p^2+9p-1=5p ?
The solutions to the equation 2p^2+9p-1=5p are p=(-2+sqrt(6))/2 ,p=-(2+sqrt(6))/2
Find the zeros of 2p^2+9p-1=5p
The zeros of 2p^2+9p-1=5p are p=(-2+sqrt(6))/2 ,p=-(2+sqrt(6))/2