What is the answer to |4x^2+8x+4|=4 ?

The answer to |4x^2+8x+4|=4 is x=-2\lor x=0

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|4x^2+8x+4|=4

4 x^{2} + 8 x + 4 = 4

x = - 2 or x = 0

Solution steps

4 x^{2} + 8 x + 4 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

4 x^{2} + 8 x + 4 = - 4 or 4 x^{2} + 8 x + 4 = 4

4 x^{2} + 8 x + 4 = - 4 or 4 x^{2} + 8 x + 4 = 4

No Solution or (x = - 2 or x = 0)

x = - 2 or x = 0

y - 10 \leq 14

\frac{1}{2} x - \frac{2}{3} > 3

2 b + (- 7) = - 21

3 x^{2} + 5 x - 4 = 0

4 - (2 x - 3) = 2 (2 x + 1) + 5

What is the answer to |4x^2+8x+4|=4 ?
The answer to |4x^2+8x+4|=4 is x=-2\lor x=0
Solve for x: |4x^2+8x+4|=4
The solution is x=-2\lor x=0