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Popular >

x^2+12+36>= 0

Solution

x^{2} + 12 + 36 \geq 0

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

x^{2} + 12 + 36 \geq 0

Add the numbers:

12 + 36 = 48

x^{2} + 48 \geq 0

Move

48

to the right side

x^{2} \geq - 48

If n is even,

u^{n} \geq 0

for all

u

True for all x

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\frac{1 - x}{3} - \frac{x - 1}{12} = \frac{3 x - 1}{4}

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4 ab + 6 a

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(x-3)^2=x^2+2x+1

(x - 3)^{2} = x^{2} + 2 x + 1

factor 64r^2-144r+81 factor

64 r^{2} - 144 r + 81

Frequently Asked Questions (FAQ)

What is x^2+12+36>= 0 ?
The solution to x^2+12+36>= 0 is True for all x