What are the solutions to the equation sqrt(12)x^2+6=0 ?

The solutions to the equation sqrt(12)x^2+6=0 are x=sqrt(\sqrt{3)}i,x=-sqrt(\sqrt{3)}i

Find the zeros of sqrt(12)x^2+6=0

The zeros of sqrt(12)x^2+6=0 are x=sqrt(\sqrt{3)}i,x=-sqrt(\sqrt{3)}i

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12 x^{2} + 6 = 0

x = 3 i, x = - 3 i

Solution steps

12 x^{2} + 6 = 0

Move

6

to the right side

12 x^{2} = - 6

Simplify

12 : 23

23 x^{2} = - 6

Divide both sides by

23

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

- 3 x - 6 \geq - 5

13 a^{2} - 7 a - 6

∣ 3 x ∣ < 5

x^{2} + x y + 3 x + 3 y

2 x + 1 = x - 3

What are the solutions to the equation sqrt(12)x^2+6=0 ?
The solutions to the equation sqrt(12)x^2+6=0 are x=sqrt(\sqrt{3)}i,x=-sqrt(\sqrt{3)}i
Find the zeros of sqrt(12)x^2+6=0
The zeros of sqrt(12)x^2+6=0 are x=sqrt(\sqrt{3)}i,x=-sqrt(\sqrt{3)}i