What are the solutions to the equation 5x^2-22x+8=0 ?

The solutions to the equation 5x^2-22x+8=0 are x=4,x= 2/5

Find the zeros of 5x^2-22x+8=0

The zeros of 5x^2-22x+8=0 are x=4,x= 2/5

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5 x^{2} - 22 x + 8 = 0

x = 4, x = \frac{2}{5}

Decimal Notation

x = 4, x = 0.4

Solution steps

5 x^{2} - 22 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

(- 22)^{2} - 4 \cdot 5 \cdot 8 = 18

x_{1, 2} = \frac{- ( - 22 ) \pm 18}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 18}{2 \cdot 5}, x_{2} = \frac{- ( - 22 ) - 18}{2 \cdot 5}

x = \frac{- ( - 22 ) + 18}{2 \cdot 5} : 4

x = \frac{- ( - 22 ) - 18}{2 \cdot 5} : \frac{2}{5}

The solutions to the quadratic equation are:

x = 4, x = \frac{2}{5}

16 x^{2} - 56 x + 49

(\frac{2}{3})^{- 2} + 2

3 a + 4 [c - 2 a [3 (4 - b)] + 3 c] + 3

\frac{2 π}{- 6}

x^{4} - x^{3} + x^{2} - x

What are the solutions to the equation 5x^2-22x+8=0 ?
The solutions to the equation 5x^2-22x+8=0 are x=4,x= 2/5
Find the zeros of 5x^2-22x+8=0
The zeros of 5x^2-22x+8=0 are x=4,x= 2/5