What are the solutions to the equation a^2-2a-224=0 ?

The solutions to the equation a^2-2a-224=0 are a=16,a=-14

Find the zeros of a^2-2a-224=0

The zeros of a^2-2a-224=0 are a=16,a=-14

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a^{2} - 2 a - 224 = 0

a = 16, a = - 14

Solution steps

a^{2} - 2 a - 224 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 224 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 224) = 30

a_{1, 2} = \frac{- ( - 2 ) \pm 30}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 30}{2 \cdot 1}, a_{2} = \frac{- ( - 2 ) - 30}{2 \cdot 1}

a = \frac{- ( - 2 ) + 30}{2 \cdot 1} : 16

a = \frac{- ( - 2 ) - 30}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

a = 16, a = - 14

\frac{- 1}{2} x + 1 \geq \frac{- 3}{2}

∣ x ∣ < 10

x < 4 and x > - 2

(\frac{5}{8} 3 a) (\frac{2}{5} 3 x)

x^{3} - 7 x^{2} + 7 x + 15

What are the solutions to the equation a^2-2a-224=0 ?
The solutions to the equation a^2-2a-224=0 are a=16,a=-14
Find the zeros of a^2-2a-224=0
The zeros of a^2-2a-224=0 are a=16,a=-14