What are the solutions to the equation 2(3x+1)^2=8 ?

The solutions to the equation 2(3x+1)^2=8 are x= 1/3 ,x=-1

Find the zeros of 2(3x+1)^2=8

The zeros of 2(3x+1)^2=8 are x= 1/3 ,x=-1

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2 (3 x + 1)^{2} = 8

x = \frac{1}{3}, x = - 1

Decimal Notation

x = 0.33333 \dots, x = - 1

Solution steps

2 (3 x + 1)^{2} = 8

Divide both sides by

2

(3 x + 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 1 = 4 : x = \frac{1}{3}

Solve

3 x + 1 = - 4 : x = - 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 1

\frac{x ^{5} y ^{2}}{x y ^{2}}

ln (7 x)

2 < \frac{3 - 3 x}{12} < 6

6 \cdot 7

4 x^{5} y^{4} (5 x^{5} y^{4})

What are the solutions to the equation 2(3x+1)^2=8 ?
The solutions to the equation 2(3x+1)^2=8 are x= 1/3 ,x=-1
Find the zeros of 2(3x+1)^2=8
The zeros of 2(3x+1)^2=8 are x= 1/3 ,x=-1