What are the solutions to the equation 2x^2+14x-6=x^2+7x ?

The solutions to the equation 2x^2+14x-6=x^2+7x are x=(-7+sqrt(73))/2 ,x=(-7-sqrt(73))/2

Find the zeros of 2x^2+14x-6=x^2+7x

The zeros of 2x^2+14x-6=x^2+7x are x=(-7+sqrt(73))/2 ,x=(-7-sqrt(73))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 14 x - 6 = x^{2} + 7 x

x = \frac{- 7 + 73}{2}, x = \frac{- 7 - 73}{2}

Decimal Notation

x = 0.77200 \dots, x = - 7.77200 \dots

Solution steps

2 x^{2} + 14 x - 6 = x^{2} + 7 x

Move

7 x

to the left side

2 x^{2} + 7 x - 6 = x^{2}

Move

x^{2}

to the left side

x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 6) = 73

x_{1, 2} = \frac{- 7 \pm 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 73}{2 \cdot 1}, x_{2} = \frac{- 7 - 73}{2 \cdot 1}

x = \frac{- 7 + 73}{2 \cdot 1} : \frac{- 7 + 73}{2}

x = \frac{- 7 - 73}{2 \cdot 1} : \frac{- 7 - 73}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 73}{2}, x = \frac{- 7 - 73}{2}

3.22 x + 8.99 \leq 8.22

\frac{4 n ^{4}}{6 n}

3 x - 7 = 5 (x - 5)

3 x - 1 \leq - 2 x + 9

\frac{1.66 e ^{- 11}}{400}

What are the solutions to the equation 2x^2+14x-6=x^2+7x ?
The solutions to the equation 2x^2+14x-6=x^2+7x are x=(-7+sqrt(73))/2 ,x=(-7-sqrt(73))/2
Find the zeros of 2x^2+14x-6=x^2+7x
The zeros of 2x^2+14x-6=x^2+7x are x=(-7+sqrt(73))/2 ,x=(-7-sqrt(73))/2