What is ((3x+5))/(x^2+2x-35)>= 0 ?

The solution to ((3x+5))/(x^2+2x-35)>= 0 is -7 5

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((3x+5))/(x^2+2x-35)>= 0

\frac{( 3 x + 5 )}{x ^{2} + 2 x - 35} \geq 0

- 7 < x \leq - \frac{5}{3} or x > 5

Interval Notation

(- 7, - \frac{5}{3}] \cup (5, \infty)

Decimal Notation

- 7 < x \leq - 1.66666 \dots or x > 5

Solution steps

\frac{3 x + 5}{x ^{2} + 2 x - 35} \geq 0

Factor

\frac{3 x + 5}{x ^{2} + 2 x - 35} : \frac{3 x + 5}{( x - 5 ) ( x + 7 )}

\frac{3 x + 5}{( x - 5 ) ( x + 7 )} \geq 0

Identify the intervals

- 7 < x \leq - \frac{5}{3} or x > 5

5 \leq ∣ p + 3 ∣

(3 x + 1) (5 - 10 x) > 0

- 5 x + 9 = 4

\frac{1}{1 - 2 i}

(x + 8)^{2} (x + 2) (x - 6) \geq 0

What is ((3x+5))/(x^2+2x-35)>= 0 ?
The solution to ((3x+5))/(x^2+2x-35)>= 0 is -7<x<=-5/3 \lor x>5