What are the solutions to the equation x^2+0.1x+0.0025=0 ?

The solutions to the equation x^2+0.1x+0.0025=0 are x=-0.05

Find the zeros of x^2+0.1x+0.0025=0

The zeros of x^2+0.1x+0.0025=0 are x=-0.05

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x^{2} + 0.1 x + 0.0025 = 0

x = - 0.05

Solution steps

x^{2} + 0.1 x + 0.0025 = 0

Factor

x^{2} + 0.1 x + 0.0025 : (x + 0.05)^{2}

(x + 0.05)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 0.05 = 0

Solve

x + 0.05 = 0 : x = - 0.05

The solution to the quadratic equation is:

x = - 0.05

x^{3} - x^{2} \geq 3 - 3 x

lo g_{2} (256)

6 a^{4} b^{4} c - 3 a^{3} b^{2} c - 9 a^{2} b^{2}

6 = - 5 m + 6 m

\frac{17.4}{2 \cdot 0.625}

What are the solutions to the equation x^2+0.1x+0.0025=0 ?
The solutions to the equation x^2+0.1x+0.0025=0 are x=-0.05
Find the zeros of x^2+0.1x+0.0025=0
The zeros of x^2+0.1x+0.0025=0 are x=-0.05