What are the solutions to the equation 5r^2-36r=32 ?

The solutions to the equation 5r^2-36r=32 are r=8,r=-4/5

Find the zeros of 5r^2-36r=32

The zeros of 5r^2-36r=32 are r=8,r=-4/5

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5 r^{2} - 36 r = 32

r = 8, r = - \frac{4}{5}

Decimal Notation

r = 8, r = - 0.8

Solution steps

5 r^{2} - 36 r = 32

Move

32

to the left side

5 r^{2} - 36 r - 32 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 5 ( - 32 )}{2 \cdot 5}

(- 36)^{2} - 4 \cdot 5 (- 32) = 44

r_{1, 2} = \frac{- ( - 36 ) \pm 44}{2 \cdot 5}

Separate the solutions

r_{1} = \frac{- ( - 36 ) + 44}{2 \cdot 5}, r_{2} = \frac{- ( - 36 ) - 44}{2 \cdot 5}

r = \frac{- ( - 36 ) + 44}{2 \cdot 5} : 8

r = \frac{- ( - 36 ) - 44}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

r = 8, r = - \frac{4}{5}

4 - 2 x - 6 y + 3 x y

a^{- \frac{2}{3}}

144 n^{2} + 144 n = - 36

\frac{20}{- 5}

\frac{1}{4} x + \frac{1}{8} x = - 9

What are the solutions to the equation 5r^2-36r=32 ?
The solutions to the equation 5r^2-36r=32 are r=8,r=-4/5
Find the zeros of 5r^2-36r=32
The zeros of 5r^2-36r=32 are r=8,r=-4/5