What are the solutions to the equation v^2+5v+6=0 ?

The solutions to the equation v^2+5v+6=0 are v=-2,v=-3

Find the zeros of v^2+5v+6=0

The zeros of v^2+5v+6=0 are v=-2,v=-3

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v^{2} + 5 v + 6 = 0

v = - 2, v = - 3

Solution steps

v^{2} + 5 v + 6 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

v_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 5 + 1}{2 \cdot 1}, v_{2} = \frac{- 5 - 1}{2 \cdot 1}

v = \frac{- 5 + 1}{2 \cdot 1} : - 2

v = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

v = - 2, v = - 3

9 ((x + 2)^{2}) - 4 = 2

\frac{x + 8 i}{x - 8 i}

10 x + 4 + x = 4 + 11 x - 1

3900

\frac{- 1}{4} x + 8 \leq 12

What are the solutions to the equation v^2+5v+6=0 ?
The solutions to the equation v^2+5v+6=0 are v=-2,v=-3
Find the zeros of v^2+5v+6=0
The zeros of v^2+5v+6=0 are v=-2,v=-3