What are the solutions to the equation 4x^2-28x=-45 ?

The solutions to the equation 4x^2-28x=-45 are x= 9/2 ,x= 5/2

Find the zeros of 4x^2-28x=-45

The zeros of 4x^2-28x=-45 are x= 9/2 ,x= 5/2

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4 x^{2} - 28 x = - 45

x = \frac{9}{2}, x = \frac{5}{2}

Decimal Notation

x = 4.5, x = 2.5

Solution steps

4 x^{2} - 28 x = - 45

Move

45

to the left side

4 x^{2} - 28 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 45}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 \cdot 45 = 8

x_{1, 2} = \frac{- ( - 28 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 28 ) - 8}{2 \cdot 4}

x = \frac{- ( - 28 ) + 8}{2 \cdot 4} : \frac{9}{2}

x = \frac{- ( - 28 ) - 8}{2 \cdot 4} : \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = \frac{5}{2}

(25 a^{10} b^{16})^{\frac{1}{2}}

- \frac{\frac{3}{2}}{\frac{1}{2}}

3 n^{2} - n - 14 = 0

4 ln (4)

\frac{4}{k ^{2} + 14 kn + 49 n ^{2}} \cdot \frac{k ^{2} - 49 n ^{2}}{4 k - 28 n}

What are the solutions to the equation 4x^2-28x=-45 ?
The solutions to the equation 4x^2-28x=-45 are x= 9/2 ,x= 5/2
Find the zeros of 4x^2-28x=-45
The zeros of 4x^2-28x=-45 are x= 9/2 ,x= 5/2