What are the solutions to the equation 1/5 x^2-5=0 ?

The solutions to the equation 1/5 x^2-5=0 are x=5,x=-5

Find the zeros of 1/5 x^2-5=0

The zeros of 1/5 x^2-5=0 are x=5,x=-5

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\frac{1}{5} x^{2} - 5 = 0

x = 5, x = - 5

Solution steps

\frac{1}{5} x^{2} - 5 = 0

Move

5

to the right side

\frac{1}{5} x^{2} = 5

Multiply both sides by

5

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

1 - 0.15

\frac{3 + \frac{2}{3}}{4 + \frac{2}{3}}

3 x + 1 > 10 or 3 - 4 x > 19

\frac{9 - x}{- 2} \geq - 6

(x) (x^{2})

What are the solutions to the equation 1/5 x^2-5=0 ?
The solutions to the equation 1/5 x^2-5=0 are x=5,x=-5
Find the zeros of 1/5 x^2-5=0
The zeros of 1/5 x^2-5=0 are x=5,x=-5