What are the solutions to the equation u^2-7u-8=0 ?

The solutions to the equation u^2-7u-8=0 are u=8,u=-1

Find the zeros of u^2-7u-8=0

The zeros of u^2-7u-8=0 are u=8,u=-1

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u^{2} - 7 u - 8 = 0

u = 8, u = - 1

Solution steps

u^{2} - 7 u - 8 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

u_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, u_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

u = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

u = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

u = 8, u = - 1

- 12 x = 4 x^{2} + 9

2 x^{2} - 2 x - 2 = 0

y, y^{2} - x^{2} y + 3 x^{3} = 4

- 2 x + 8 = 2

2 (x + 5) - (x + 3) = x + 7

What are the solutions to the equation u^2-7u-8=0 ?
The solutions to the equation u^2-7u-8=0 are u=8,u=-1
Find the zeros of u^2-7u-8=0
The zeros of u^2-7u-8=0 are u=8,u=-1