What is the answer to 4(3f-2)+16=8(f+3)-(13-2f) ?

The answer to 4(3f-2)+16=8(f+3)-(13-2f) is f= 3/2

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4(3f-2)+16=8(f+3)-(13-2f)

4 (3 f - 2) + 16 = 8 (f + 3) - (13 - 2 f)

f = \frac{3}{2}

Decimal Notation

f = 1.5

Solution steps

4 (3 f - 2) + 16 = 8 (f + 3) - (13 - 2 f)

Expand

4 (3 f - 2) + 16 : 12 f + 8

Expand

8 (f + 3) - (13 - 2 f) : 10 f + 11

12 f + 8 = 10 f + 11

Move

8

to the right side

12 f = 10 f + 3

Move

10 f

to the left side

2 f = 3

Divide both sides by

2

f = \frac{3}{2}

4 x + 5 + x = 7 + 3 x - 3

\frac{64}{169}

\frac{36 b ^{4} c ^{2}}{9 b ^{- 1} c ^{5}}

25 x^{2} + 10 x + 1

(x + y) (x - y)

What is the answer to 4(3f-2)+16=8(f+3)-(13-2f) ?
The answer to 4(3f-2)+16=8(f+3)-(13-2f) is f= 3/2
Solve for f: 4(3f-2)+16=8(f+3)-(13-2f)
The solution is f= 3/2