What are the solutions to the equation 2x^2+5x=12 ?

The solutions to the equation 2x^2+5x=12 are x= 3/2 ,x=-4

Find the zeros of 2x^2+5x=12

The zeros of 2x^2+5x=12 are x= 3/2 ,x=-4

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2 x^{2} + 5 x = 12

x = \frac{3}{2}, x = - 4

Decimal Notation

x = 1.5, x = - 4

Solution steps

2 x^{2} + 5 x = 12

Move

12

to the left side

2 x^{2} + 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 12) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 2}, x_{2} = \frac{- 5 - 11}{2 \cdot 2}

x = \frac{- 5 + 11}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 5 - 11}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 4

2 x^{2} + 4 x + 8

8 x + 12 = 24

3 x = 45

x^{2} (x + h)^{2}

x^{2} - 3 x - 5 = 0

What are the solutions to the equation 2x^2+5x=12 ?
The solutions to the equation 2x^2+5x=12 are x= 3/2 ,x=-4
Find the zeros of 2x^2+5x=12
The zeros of 2x^2+5x=12 are x= 3/2 ,x=-4