What are the solutions to the equation 4x^2-2x(3x+1)=5 ?

The solutions to the equation 4x^2-2x(3x+1)=5 are x=-1/2-i 3/2 ,x=-1/2+i 3/2

Find the zeros of 4x^2-2x(3x+1)=5

The zeros of 4x^2-2x(3x+1)=5 are x=-1/2-i 3/2 ,x=-1/2+i 3/2

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4 x^{2} - 2 x (3 x + 1) = 5

x = - \frac{1}{2} - i \frac{3}{2}, x = - \frac{1}{2} + i \frac{3}{2}

Solution steps

4 x^{2} - 2 x (3 x + 1) = 5

Expand

4 x^{2} - 2 x (3 x + 1) : - 2 x^{2} - 2 x

- 2 x^{2} - 2 x = 5

Move

5

to the left side

- 2 x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

Simplify

(- 2)^{2} - 4 (- 2) (- 5) : 6 i

x_{1, 2} = \frac{- ( - 2 ) \pm 6 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 2 ) - 6 i}{2 ( - 2 )}

x = \frac{- ( - 2 ) + 6 i}{2 ( - 2 )} : - \frac{1}{2} - i \frac{3}{2}

x = \frac{- ( - 2 ) - 6 i}{2 ( - 2 )} : - \frac{1}{2} + i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} - i \frac{3}{2}, x = - \frac{1}{2} + i \frac{3}{2}

∣ x + 7 ∣ - 2 = 8

5 (x - 1.5) = 22.5

\frac{a + 1}{3} - a

9 - 7

8 x^{2} - 22 x + 15

What are the solutions to the equation 4x^2-2x(3x+1)=5 ?
The solutions to the equation 4x^2-2x(3x+1)=5 are x=-1/2-i 3/2 ,x=-1/2+i 3/2
Find the zeros of 4x^2-2x(3x+1)=5
The zeros of 4x^2-2x(3x+1)=5 are x=-1/2-i 3/2 ,x=-1/2+i 3/2