What are the solutions to the equation (x-4)^2=-12 ?

The solutions to the equation (x-4)^2=-12 are x=2sqrt(3)i+4,x=-2sqrt(3)i+4

Find the zeros of (x-4)^2=-12

The zeros of (x-4)^2=-12 are x=2sqrt(3)i+4,x=-2sqrt(3)i+4

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(x - 4)^{2} = - 12

x = 23 i + 4, x = - 23 i + 4

Solution steps

(x - 4)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 12 : x = 23 i + 4

Solve

x - 4 = - - 12 : x = - 23 i + 4

The solutions to the quadratic equation are:

x = 23 i + 4, x = - 23 i + 4

a^{2} - 4 a - 12

6 x^{2} - \frac{1}{2} x - \frac{1}{4} = 0

(\frac{x ^{- 8}}{y ^{11}})^{- 2}

- 3 - 2

What are the solutions to the equation (x-4)^2=-12 ?
The solutions to the equation (x-4)^2=-12 are x=2sqrt(3)i+4,x=-2sqrt(3)i+4
Find the zeros of (x-4)^2=-12
The zeros of (x-4)^2=-12 are x=2sqrt(3)i+4,x=-2sqrt(3)i+4