What are the solutions to the equation x^2+3x-24=0 ?

The solutions to the equation x^2+3x-24=0 are x=(-3+sqrt(105))/2 ,x=(-3-sqrt(105))/2

Find the zeros of x^2+3x-24=0

The zeros of x^2+3x-24=0 are x=(-3+sqrt(105))/2 ,x=(-3-sqrt(105))/2

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x^{2} + 3 x - 24 = 0

x = \frac{- 3 + 105}{2}, x = \frac{- 3 - 105}{2}

Solution steps

x^{2} + 3 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 24) = 105

x_{1, 2} = \frac{- 3 \pm 105}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 105}{2 \cdot 1}, x_{2} = \frac{- 3 - 105}{2 \cdot 1}

x = \frac{- 3 + 105}{2 \cdot 1} : \frac{- 3 + 105}{2}

x = \frac{- 3 - 105}{2 \cdot 1} : \frac{- 3 - 105}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 105}{2}, x = \frac{- 3 - 105}{2}

20 x^{2} - 9 x - 20

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What are the solutions to the equation x^2+3x-24=0 ?
The solutions to the equation x^2+3x-24=0 are x=(-3+sqrt(105))/2 ,x=(-3-sqrt(105))/2
Find the zeros of x^2+3x-24=0
The zeros of x^2+3x-24=0 are x=(-3+sqrt(105))/2 ,x=(-3-sqrt(105))/2