What are the solutions to the equation 6x^2+9x+3=0 ?

The solutions to the equation 6x^2+9x+3=0 are x=-1/2 ,x=-1

Find the zeros of 6x^2+9x+3=0

The zeros of 6x^2+9x+3=0 are x=-1/2 ,x=-1

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6 x^{2} + 9 x + 3 = 0

x = - \frac{1}{2}, x = - 1

Decimal Notation

x = - 0.5, x = - 1

Solution steps

6 x^{2} + 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

9^{2} - 4 \cdot 6 \cdot 3 = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 \cdot 6}, x_{2} = \frac{- 9 - 3}{2 \cdot 6}

x = \frac{- 9 + 3}{2 \cdot 6} : - \frac{1}{2}

x = \frac{- 9 - 3}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 1

- 9 v - 5 + 6 v = 19

(2 x - 3)^{2} + (x - 2)^{2} = 3 (x + 1) + 5 x (x - 1)

m < \frac{1}{2} (13 - 43)

4 (\frac{1}{5})

m^{6} - 125

What are the solutions to the equation 6x^2+9x+3=0 ?
The solutions to the equation 6x^2+9x+3=0 are x=-1/2 ,x=-1
Find the zeros of 6x^2+9x+3=0
The zeros of 6x^2+9x+3=0 are x=-1/2 ,x=-1