What are the solutions to the equation -x^2-4x+3=0 ?

The solutions to the equation -x^2-4x+3=0 are x=-2-sqrt(7),x=sqrt(7)-2

Find the zeros of -x^2-4x+3=0

The zeros of -x^2-4x+3=0 are x=-2-sqrt(7),x=sqrt(7)-2

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- x^{2} - 4 x + 3 = 0

x = - 2 - 7, x = 7 - 2

Decimal Notation

x = - 4.64575 \dots, x = 0.64575 \dots

Solution steps

- x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) \cdot 3 = 27

x_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 7}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 2 7}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 2 7}{2 ( - 1 )} : - 2 - 7

x = \frac{- ( - 4 ) - 2 7}{2 ( - 1 )} : 7 - 2

The solutions to the quadratic equation are:

x = - 2 - 7, x = 7 - 2

6 n^{2} + 5 n - 6

5 x - 7 < 13

y, x + y = 5

\frac{x}{2} + \frac{13}{10} = \frac{13 - x}{2}

- 16 n = 241.6

What are the solutions to the equation -x^2-4x+3=0 ?
The solutions to the equation -x^2-4x+3=0 are x=-2-sqrt(7),x=sqrt(7)-2
Find the zeros of -x^2-4x+3=0
The zeros of -x^2-4x+3=0 are x=-2-sqrt(7),x=sqrt(7)-2