What is factor 4m^2+20m+25 ?

The solution to factor 4m^2+20m+25 is (2m+5)^2

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factor 4m^2+20m+25

factor

4 m^{2} + 20 m + 25

(2 m + 5)^{2}

Solution steps

4 m^{2} + 20 m + 25

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 m^{2} = (2 m)^{2}

25 = 5^{2}

20 m = 2 \cdot 2 m \cdot 5

= (2 m)^{2} + 2 \cdot 2 m \cdot 5 + 5^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 m)^{2} + 2 \cdot 2 m \cdot 5 + 5^{2} = (2 m + 5)^{2}

= (2 m + 5)^{2}

6 (p - 2) - 3 = 2 p + 20

3 9^{2}

\frac{x}{x ^{2}}

\frac{4 x - 3}{5} + 2 \leq \frac{x - 1}{15}

(\frac{x ^{6} - 1}{2 x ^{3}})^{2}