What are the solutions to the equation 6x^2+5x-7=0 ?

The solutions to the equation 6x^2+5x-7=0 are x=(-5+sqrt(193))/(12),x=(-5-sqrt(193))/(12)

Find the zeros of 6x^2+5x-7=0

The zeros of 6x^2+5x-7=0 are x=(-5+sqrt(193))/(12),x=(-5-sqrt(193))/(12)

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6 x^{2} + 5 x - 7 = 0

x = \frac{- 5 + 193}{12}, x = \frac{- 5 - 193}{12}

Decimal Notation

x = 0.74103 \dots, x = - 1.57437 \dots

Solution steps

6 x^{2} + 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 7) = 193

x_{1, 2} = \frac{- 5 \pm 193}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 193}{2 \cdot 6}, x_{2} = \frac{- 5 - 193}{2 \cdot 6}

x = \frac{- 5 + 193}{2 \cdot 6} : \frac{- 5 + 193}{12}

x = \frac{- 5 - 193}{2 \cdot 6} : \frac{- 5 - 193}{12}

The solutions to the quadratic equation are:

x = \frac{- 5 + 193}{12}, x = \frac{- 5 - 193}{12}

∣ 3 - 2 r ∣ > 7

(\frac{1}{7})^{- 1}

\frac{- 5}{2} \cdot 2

\frac{k ^{14} + 4 k ^{7} + 3}{2 k ^{11} + 2 k ^{4}}

8 8 n + 8 8 n

What are the solutions to the equation 6x^2+5x-7=0 ?
The solutions to the equation 6x^2+5x-7=0 are x=(-5+sqrt(193))/(12),x=(-5-sqrt(193))/(12)
Find the zeros of 6x^2+5x-7=0
The zeros of 6x^2+5x-7=0 are x=(-5+sqrt(193))/(12),x=(-5-sqrt(193))/(12)