What are the solutions to the equation 4x^2=2 ?

The solutions to the equation 4x^2=2 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 4x^2=2

The zeros of 4x^2=2 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} = 2

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

4 x^{2} = 2

Divide both sides by

4

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

- 2 x + 11 = - 2 x - 8

5 x - 104 = 106 + 15 x

\frac{1}{4 π ( 3 + 2 ) ^{2}} (- 11)

3 ∣ 9 x + 5 ∣ + 8 > 20

\frac{- 20 + 4 i}{3 + 2 i}

What are the solutions to the equation 4x^2=2 ?
The solutions to the equation 4x^2=2 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 4x^2=2
The zeros of 4x^2=2 are x= 1/(sqrt(2)),x=-1/(sqrt(2))