What are the solutions to the equation -x^2-1.5x+5=7 ?

The solutions to the equation -x^2-1.5x+5=7 are x=-3/4-i(sqrt(23))/4 ,x=-3/4+i(sqrt(23))/4

Find the zeros of -x^2-1.5x+5=7

The zeros of -x^2-1.5x+5=7 are x=-3/4-i(sqrt(23))/4 ,x=-3/4+i(sqrt(23))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} - 1.5 x + 5 = 7

x = - \frac{3}{4} - i \frac{23}{4}, x = - \frac{3}{4} + i \frac{23}{4}

Solution steps

- x^{2} - 1.5 x + 5 = 7

Multiply both sides by

10

- 10 x^{2} - 15 x + 50 = 70

Move

70

to the left side

- 10 x^{2} - 15 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 ( - 10 ) ( - 20 )}{2 ( - 10 )}

Simplify

(- 15)^{2} - 4 (- 10) (- 20) : 523 i

x_{1, 2} = \frac{- ( - 15 ) \pm 5 23 i}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 5 23 i}{2 ( - 10 )}, x_{2} = \frac{- ( - 15 ) - 5 23 i}{2 ( - 10 )}

x = \frac{- ( - 15 ) + 5 23 i}{2 ( - 10 )} : - \frac{3}{4} - i \frac{23}{4}

x = \frac{- ( - 15 ) - 5 23 i}{2 ( - 10 )} : - \frac{3}{4} + i \frac{23}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} - i \frac{23}{4}, x = - \frac{3}{4} + i \frac{23}{4}

x^{2} - 3 x + 8 \geq 0

(\frac{1}{x ^{2} - 3 x - 4})^{\frac{1}{2}}

8 a + 16 c

15 x^{2} + 7 x - 2

h (- 2) = 7^{- 2}

What are the solutions to the equation -x^2-1.5x+5=7 ?
The solutions to the equation -x^2-1.5x+5=7 are x=-3/4-i(sqrt(23))/4 ,x=-3/4+i(sqrt(23))/4
Find the zeros of -x^2-1.5x+5=7
The zeros of -x^2-1.5x+5=7 are x=-3/4-i(sqrt(23))/4 ,x=-3/4+i(sqrt(23))/4