What are the solutions to the equation 1^2+5^2=c^2 ?

The solutions to the equation 1^2+5^2=c^2 are c=sqrt(26),c=-sqrt(26)

Find the zeros of 1^2+5^2=c^2

The zeros of 1^2+5^2=c^2 are c=sqrt(26),c=-sqrt(26)

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1^{2} + 5^{2} = c^{2}

c = 26, c = - 26

Decimal Notation

c = 5.09901 \dots, c = - 5.09901 \dots

Solution steps

1^{2} + 5^{2} = c^{2}

Switch sides

c^{2} = 1^{2} + 5^{2}

Simplify

1^{2} + 5^{2} : 26

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 26, c = - 26

- 2 k \leq - 6

\frac{x - 1}{x ^{2} - 1}

- \frac{1}{5} = \frac{1}{3} m - \frac{4}{5} m

∣ x ∣ - 2 = 0

2 x - 2 \leq 6 and 4 x + 2 > - 22

What are the solutions to the equation 1^2+5^2=c^2 ?
The solutions to the equation 1^2+5^2=c^2 are c=sqrt(26),c=-sqrt(26)
Find the zeros of 1^2+5^2=c^2
The zeros of 1^2+5^2=c^2 are c=sqrt(26),c=-sqrt(26)