What are the solutions to the equation c^2+5c=14 ?

The solutions to the equation c^2+5c=14 are c=2,c=-7

Find the zeros of c^2+5c=14

The zeros of c^2+5c=14 are c=2,c=-7

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c^{2} + 5 c = 14

c = 2, c = - 7

Solution steps

c^{2} + 5 c = 14

Move

14

to the left side

c^{2} + 5 c - 14 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

c_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 5 + 9}{2 \cdot 1}, c_{2} = \frac{- 5 - 9}{2 \cdot 1}

c = \frac{- 5 + 9}{2 \cdot 1} : 2

c = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

c = 2, c = - 7

\frac{19 - 20}{0.53}

a^{4} - 5 a^{2} - 36

\frac{2}{5} x = - \frac{1}{10}

\frac{3 x - 2}{12} - \frac{1}{6} = \frac{1}{6}

What are the solutions to the equation c^2+5c=14 ?
The solutions to the equation c^2+5c=14 are c=2,c=-7
Find the zeros of c^2+5c=14
The zeros of c^2+5c=14 are c=2,c=-7