What are the solutions to the equation (y+2)(y-6)=0 ?

The solutions to the equation (y+2)(y-6)=0 are y=-2,y=6

Find the zeros of (y+2)(y-6)=0

The zeros of (y+2)(y-6)=0 are y=-2,y=6

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(y + 2) (y - 6) = 0

y = - 2, y = 6

Solution steps

(y + 2) (y - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 2 = 0 or y - 6 = 0

Solve

y + 2 = 0 : y = - 2

Solve

y - 6 = 0 : y = 6

The solutions to the quadratic equation are:

y = - 2, y = 6

(- 3 i)^{3}

8 t - 0.8 t - 10 = 0

6 m - 9 n + 21 n x - 14 m x

x^{2} + 6 x - 27 \geq 0

y, y^{2} = x^{3} + 48662 \cdot x^{2} + x

What are the solutions to the equation (y+2)(y-6)=0 ?
The solutions to the equation (y+2)(y-6)=0 are y=-2,y=6
Find the zeros of (y+2)(y-6)=0
The zeros of (y+2)(y-6)=0 are y=-2,y=6