What are the solutions to the equation 9x^2+11x+3=0 ?

The solutions to the equation 9x^2+11x+3=0 are x=(-11+sqrt(13))/(18),x=(-11-sqrt(13))/(18)

Find the zeros of 9x^2+11x+3=0

The zeros of 9x^2+11x+3=0 are x=(-11+sqrt(13))/(18),x=(-11-sqrt(13))/(18)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 11 x + 3 = 0

x = \frac{- 11 + 13}{18}, x = \frac{- 11 - 13}{18}

Decimal Notation

x = - 0.41080 \dots, x = - 0.81141 \dots

Solution steps

9 x^{2} + 11 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 9 \cdot 3}{2 \cdot 9}

1 1^{2} - 4 \cdot 9 \cdot 3 = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 9}, x_{2} = \frac{- 11 - 13}{2 \cdot 9}

x = \frac{- 11 + 13}{2 \cdot 9} : \frac{- 11 + 13}{18}

x = \frac{- 11 - 13}{2 \cdot 9} : \frac{- 11 - 13}{18}

The solutions to the quadratic equation are:

x = \frac{- 11 + 13}{18}, x = \frac{- 11 - 13}{18}

6 x = 9 x^{2}

(2 5 y)^{2}

62 - 38

12 x^{2} - 22 x + 8

x - 7 \geq 2

What are the solutions to the equation 9x^2+11x+3=0 ?
The solutions to the equation 9x^2+11x+3=0 are x=(-11+sqrt(13))/(18),x=(-11-sqrt(13))/(18)
Find the zeros of 9x^2+11x+3=0
The zeros of 9x^2+11x+3=0 are x=(-11+sqrt(13))/(18),x=(-11-sqrt(13))/(18)