en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-x^2+5x-7<= 0

Solution

- x^{2} + 5 x - 7 \leq 0

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

- x^{2} + 5 x - 7 \leq 0

Complete the square

- x^{2} + 5 x - 7 : - (x - \frac{5}{2})^{2} - \frac{3}{4}

- (x - \frac{5}{2})^{2} - \frac{3}{4} \leq 0

Move

\frac{3}{4}

to the right side

- (x - \frac{5}{2})^{2} \leq \frac{3}{4}

Multiply both sides by

- 1

(x - \frac{5}{2})^{2} \geq - \frac{3}{4}

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

6x^3-11x^2-10x>= 0

6 x^{3} - 11 x^{2} - 10 x \geq 0

4.8 x + 7.48 = - 5

simplify 2/(3i)simplify

\frac{2}{3 i}

factor x^2-19x+60 factor

x^{2} - 19 x + 60

factor 9r^2-36r-45 factor

9 r^{2} - 36 r - 45

Frequently Asked Questions (FAQ)

What is -x^2+5x-7<= 0 ?
The solution to -x^2+5x-7<= 0 is True for all x