What are the solutions to the equation x^2+3x=54 ?

The solutions to the equation x^2+3x=54 are x=6,x=-9

Find the zeros of x^2+3x=54

The zeros of x^2+3x=54 are x=6,x=-9

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x^{2} + 3 x = 54

x = 6, x = - 9

Solution steps

x^{2} + 3 x = 54

Move

54

to the left side

x^{2} + 3 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 54) = 15

x_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 15}{2 \cdot 1}, x_{2} = \frac{- 3 - 15}{2 \cdot 1}

x = \frac{- 3 + 15}{2 \cdot 1} : 6

x = \frac{- 3 - 15}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 6, x = - 9

4 r^{2} - 12 r + 9 = 0

\frac{4}{5 x} + \frac{1}{10} < \frac{3}{2 x}

- 0.000005 x^{2} + 0.0004 x + 0.4983 = 0

- 327

\frac{15 - ( - 3 )}{9} + (- 2) + (5) (- 7)

What are the solutions to the equation x^2+3x=54 ?
The solutions to the equation x^2+3x=54 are x=6,x=-9
Find the zeros of x^2+3x=54
The zeros of x^2+3x=54 are x=6,x=-9